SAT I 一日一问：2012年12月18日

The Correct answer is D.

Explanation

Since exactly two of the four lines are parallel, the other two lines are not parallel. If the two non-parallel lines intersect at a point that is not on either one of the parallel lines, then the configuration of lines will give a total of 5 points of intersection. (The best way to verify this is by drawing the two parallel lines and then putting in the other two lines.) If, on the other hand, the two non-parallel lines intersect at a point that is on one of the parallel lines, then there will be a total of 3 points of intersection in the figure. (Again, a sketch is the best way to verify this.) Any arrangement of the four lines will again yield either 3 or 5 points of intersection. Since you can’t obtain four points of intersection, the correct answer is I and III only.

你可能还感兴趣的相关文章

• 美国高考作文题目汇总：SAT写作历年题目

  美国“高考(SAT)”的写作或作文题目是什么样的呢？小编整理了2012到2015年美国高考的作文题目也就是SAT写作历年题目让大家练练手。

• 【真题解析】详解新SAT语法考试中易混淆词汇题答题技巧
• SAT I 一日一问：2015年3月5日
• SAT I 一日一问：2015年3月4日
• SAT I 一日一问：2015年3月3日

最新2024SAT真题信息由沪江留学网提供。